![]() Of the patch could be in static friction state when I have a Of the contact patch slides, because I can't really well see how 80% This means that for the tyre to generate maximum force the totality Typical road tyre generates maximum force at slip ratios between 10Īnd 20%, and doesn't generate anything significant when slip ratio isĠ. Measured at the previous simulation step. Ratio: it is the ratio of the two velocities I mentioned previously, On the resultant of all torques, and the wheel inertia (plusīut Pacejka magic formula takes as input a totally different slip Resulting force is the same, and wheel angular velocity change depends If slip ratio is 100%, then the wheel slides,Īnd the generated force is constant: whatever the velocity delta, the Tangential velocity (radius x angular velocity x 2PI) more or less Wheel model, as long as slip ratio is not 100%, at contact patch wheel Pushed down on the ground as the wheel rolls). (fore area of the patch, pressed into adherence by the tread being Is lifted as the wheel rolls) over the part that adheres on the ground ![]() I've readīut there are still some contradictions I don't grasp.įrom what I understand, in real life, slip ratio is the proportion ofĬontact patch that is sliding (usually the aft part as the wheel tread Interpret it to generate proper wheel angular velocities. ![]() To understand how slip ratio is to be interpreted and how I should I am trying to code my own car simulator, and have some difficulties ![]()
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